fișierul txt există, dar python nu îl găsește

import subprocess
def main():
path = r'D:\temp2\pyscr\dir output.txt'
print(path)
f = open(path, 'w')
subprocess.run(["dir", "/b"], stdout=f)

if __name__ == "__main__": main()

D:\temp2\pyscr\dir output.txt
Traceback (most recent call last):
File "D:\projects\Manage youtube clips\tmp code to view.py", line 9, in <module>
if __name__ == "__main__": main()
File "D:\projects\Manage youtube clips\tmp code to view.py", line 7, in main
subprocess.run(["dir", "/b"], stdout=f)
File "C:\Python35\lib\subprocess.py", line 696, in run
with Popen(*popenargs, **kwargs) as process:
File "C:\Python35\lib\subprocess.py", line 950, in __init__
restore_signals, start_new_session)
File "C:\Python35\lib\subprocess.py", line 1220, in _execute_child
startupinfo)
FileNotFoundError: [WinError 2] The system cannot find the file specified

Edited by CTU99, 20 March 2016 - 00:16.

path = 'D:\temp2\pyscr\dir output.txt'

path = 'D:\\temp2\\pyscr\\dir output.txt'

Edited by Konatau, 20 March 2016 - 01:03.

subprocess.run(["dir", "/b"], stdout=f)

subprocess.run(["C:\Windows\System32\cmd.exe", "dir", "/b"], stdout=f)

Edited by CTU99, 20 March 2016 - 02:51.

Konatau, on 20 martie 2016 - 01:02, said:

path = 'D:\temp2\pyscr\dir output.txt'

path = 'D:\\temp2\\pyscr\\dir output.txt'

path = r'D:\temp2\pyscr\dir output.txt'

path = 'D:\\temp2\\pyscr\\dir output.txt'

>>> s1 = r'D:\temp2\pyscr\dir output.txt'
>>> s2 = 'D:\\temp2\\pyscr\\dir output.txt'
>>> s1 == s2
True

Edited by CTU99, 20 March 2016 - 03:16.

C:\Windows\System32\cmd.exe

%windir%\system32\cmd.exe

Edited by xxvirusxx, 20 March 2016 - 20:56.