strtok string;

Salut.Vreau sa desfac in tokens un sir de caractere.Am urmatoarul program.

#include <iostream>
#include <string.h>
using namespace std;
int main()
{
char str[30] = "mare frig rosu";
char s[10]=" ,.-;:";
//cin>>str;
char * pch;
cout<<str<<endl;
pch = strtok (str,s);
while (pch != NULL)
{
	 cout<<pch<<endl;
	 pch = strtok (NULL,s);
}
return 0;
}

care merge perfect ,  si imi afiseaza

mare
frig
rosu

Dar daca citesc sirul , adica am asa:

char str[30];
char s[10]=" ,.-;:";
cin>>str;
char * pch;
cout<<str<<endl;
pch = strtok (str,s);
while (pch != NULL)
{
	 cout<<pch<<endl;
	 pch = strtok (NULL,s);
}

imi afiseaza:

mare
mare

Nu inteleg , am luat si cu debug si nu-mi pica fisa.Multam fain!

Edited by stefanutz13, 26 May 2015 - 20:56.

Ai alternative mai bune în c++ decât `strtok`.

#include <iostream>
#include <string>
#include <vector>
#include <boost/algorithm/string.hpp>

int main()
{
	std::string toSplit = "mare mar rosu";
	std::vector<std::string> tokens;

	boost::split(tokens, toSplit, boost::is_any_of(" "));

	for(auto const& token : tokens)
	{
		std::cout << token << std::endl;
	}

	return 0;
}

Vezi mai multe aici.

De asemenea, asta:

#include <string.h>

ar trebui inlocuita cu asta

#include <cstring>

Edited by cd9, 27 May 2015 - 00:02.

stefanutz13, on 26 mai 2015 - 20:56, said:

cin>>str

iti citeste pana la spatiu. Foloseste cin.getline()

Edited by nightmare392, 27 May 2015 - 20:44.

@nightmare , mi-am dat seama dupa.Ms oricum.Have a nice banana day ))

strtok insereaza terminatori in str, si nu se mai recomanda folosirea sa.

Edited by TS030, 28 May 2015 - 11:58.