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Indice saponificare
Last Updated: Jul 29 2018 22:31, Started by
Gumbal
, Jul 29 2018 20:41
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#2
Posted 29 July 2018 - 21:40
#3
Posted 29 July 2018 - 21:53
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Yourdad, on 29 iulie 2018 - 21:40, said: Nu sunt sigur daca ce am facut e bine, dar mie mi a dat asa 25ml KOH 0.5N Echivalent gram = 56,1056(-masa molara)/ 1( nr de grupari oH ) = 56,1056 daca 0.5N.......1000ml x N......... 25ml x=0.0125 N=> 0.0125N * 56.1056= 0,70132 grame la 25 ml La 1 ml => 0,70132 /25= 28.05 mg KOH Edited by Gumbal, 29 July 2018 - 21:53. |
#4
Posted 29 July 2018 - 22:15
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Cred ca s-a calculat masa molara a lui KOH cu masele atomice nerontunjite
AK = 39,0983 AO = 15,999 AH = 1,00794 MKOH = 56,10524 1 Eg KOH = 56,10524 g 0,5 x 10-3 Eg KOH = 0,5 x 10-3 x 56,10524 = 28,052 x 10-3 g = 28,052 mg Nu stiu de unde le-a dat 28,055 mg De ce ai luat 25 ml? Edited by aerdem, 29 July 2018 - 22:22. |
#5
Posted 29 July 2018 - 22:25
#6
Posted 29 July 2018 - 22:31
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Aha, Nu am tinut cont. Am zis ca 0,5 x 10-3 echivalenti gram de HCl (cati sunt in 1 mL solutie) reactioneaza cu 0,5 x 10-3 echivalenti gram KOH (conform legii echivalentei) si am calculat cat au 0,5 x 10-3 echivalenti gram de KOH
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