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Chirurgia cranio-cerebrală minim invazivă
Tehnicile minim invazive impun utilizarea unei tehnologii ultramoderne. Endoscoapele operatorii de diverse tipuri, microscopul operator dedicat, neuronavigația, neuroelectrofiziologia, tehnicile avansate de anestezie, chirurgia cu pacientul treaz reprezintă armamentarium fără de care neurochirurgia prin "gaura cheii" nu ar fi posibilă. Folosind tehnicile de mai sus, tratăm un spectru larg de patologii cranio-cerebrale. www.neurohope.ro |
Problema SQL Join
Last Updated: Mar 26 2016 17:03, Started by
93kts
, Mar 26 2016 12:13
·
0
0
#1
Posted 26 March 2016 - 12:13
|
Buna ziua !
Ma poate ajuta cineva cu : SELECT c.* , p.* FROM cotos_escorte c,cotos_poze_escorte p WHERE c.id=p.e_id preia corect dar as vrea pentru tabela cotos_escorte sa-mi afiseze doar 10 iar pentru cotos_poze_escorte doar 1.. Cum pot face ? |
#2
Posted 26 March 2016 - 13:32
|
select top 10 *
from (Select row_number() over (partition by c.id order by p.id) as Part_id, c.id as ce_id, p.id as cpe_id, * from cotos_escorte c inner join cotos_poze_escorte p on c.id=p.e_id order by c.id, p.id) x where x.part_id = 1 order by x.ce_id Daca baza de date este MSSQL, regasesti la link-ul urmator mai multe informatii: https://msdn.microso...y/ms189461.aspx |
#3
Posted 26 March 2016 - 13:56
|
select top 10 * from (Select row_number() over (partition by c.id order by p.id) as Part_id, c.id as ce_id, p.id as cpe_id, * from cotos_escorte c inner join cotos_poze_escorte p on c.id=p.e_id order by c.id, p.id) x where x.part_id = 1 order by x.ce_id Daca baza de date este MSSQL, regasesti la link-ul urmator mai multe informatii: https://msdn.microso...y/ms189461.aspx Mersi mult ! Acum incerc sa vad ce iese ! :-D Imi da : mysql_fetch_array() expects parameter 1 to be resource, Edited by 93kts, 26 March 2016 - 14:03. |
#4
Posted 26 March 2016 - 17:03
|
Mda, in Mysql trebuie pusa o virguala intre ...partiton by c.id, order by p.id...
Ex: http://stackoverflow...number-in-mysql |
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